A Primer for Cross Product Calculations
š§ A Primer for Cross Product Calculations
Right Hand Rule for Cross Product. Source: https://commons.wikimedia.org/wiki/File:Right-hand_rule_for_cross_product.png
1. Basis Vectors
î = (1, 0, 0), ĵ = (0, 1, 0), k̂ = (0, 0, 1)
These are unit and mutually perpendicular vectors.
2. Dot Product (for reference)
š · š = |š| |š| cos Īø
î · ĵ = ĵ · k̂ = k̂ · î = 0
î² = ĵ² = k̂² = 1
3. Definition of the Cross Product
š × š = |š| |š| sin Īø n̂
- Īø is the angle from š to š.
- n̂ is a unit vector perpendicular to both š and š.
- The direction of n̂ follows the right-hand rule (anticlockwise = positive, clockwise = negative).
4. Fundamental Basis Cross Products
î × ĵ = k̂ ĵ × k̂ = î k̂ × î = ĵ
Reversing the order changes the sign:
ĵ × î = −k̂ k̂ × ĵ = −î î × k̂ = −ĵ
And any vector crossed with itself is zero:
î × î = ĵ × ĵ = k̂ × k̂ = 0
5. Expansion in Component Form
š = a₁ î + a₂ ĵ + a₃ k̂
š = b₁ î + b₂ ĵ + b₃ k̂
By distributivity:
š × š = (a₂b₃ − a₃b₂) î + (a₃b₁ − a₁b₃) ĵ + (a₁b₂ − a₂b₁) k̂
6. Determinant Representation
| î ĵ k̂ |
š × š = | a₁ a₂ a₃ |
| b₁ b₂ b₃ |
Expanding this determinant:
š × š =
î |a₂ a₃|
|b₂ b₃|
− ĵ |a₁ a₃|
|b₁ b₃|
+ k̂ |a₁ a₂|
|b₁ b₂|
This is simply a compact way to remember the component formula above.
7. Computational Formula
For quick calculations:
š × š = (a₂b₃ − a₃b₂, a₃b₁ − a₁b₃, a₁b₂ − a₂b₁)
8. Geometric Interpretation
- š × š is perpendicular to both š and š.
- Its magnitude equals the area of the parallelogram spanned by š and š:
|š × š| = |š| |š| sin Īø
The direction follows the right-hand rule.
✅ Summary Table
| Operation | Result |
|---|---|
| î × ĵ | + k̂ |
| ĵ × k̂ | + î |
| k̂ × î | + ĵ |
| Reversed order | Negative result |
| Same vectors | 0 |
| Magnitude | |š| |š| sin Īø |
| Direction | Perpendicular to both (right-hand rule) |
From this foundation, all 3D cross products can be computed directly and visualised geometrically.
© mathematics.proofs

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