Geometric Bites

Below I demonstrate how to derive tan(π/8) , sin(π/8) and cos(π/8) from scratch. These workings are a bit similar to the workings for tan((3π)/8) , sin((3π)/8) and cos((3π)/8) which can be found here : https://geometricbites.blogspot.com/2021/08/how-to-derive-tan38-sin38-and-cos38.html The edge with length R √(2- √(2)) was actually derived in the tan((3π)/8), sin((3π)/8) and cos((3π)/8) post, so doesn't need to be found again. Part 1  Part 2  Part 3  Part 4

Recently, I produced some recursive geometric art that got a pretty good amount of attention on the internet. Here it is: So, what was the secret of its success? It was a solid geometric drawing I made beforehand. With that solid geometric drawing, I was able to see the proportions required to produce my animation. There is a clarity that geometric drawings bring because of their rigidity . As you can see in the image above, the squares get smaller . Their lengths decrease by a factor of 1/2 with each iteration . When these lengths are applied to vertical and horizontal lines what you get is pure mathematical magic... The pattern in my video. How about the equations ? Well, if I tell you everything it would be like revealing the entire story of a great movie before you've watched it. I would hate to spoil your creative experience. :-)

This proof solves a popular internet geometry problem found here: https://twitter.com/RonySarker71/status/1428469920443076609 By utilising the radius of the circle , one can arrive at the conclusion that y= √(ax). If a=1, then you get y= √(x).