How to derive tan(π/8), sin(π/8) and cos(π/8) from scratch

Below I demonstrate how to derive tan(π/8), sin(π/8) and cos(π/8) from scratch. These workings are a bit similar to the workings for tan((3π)/8), sin((3π)/8) and cos((3π)/8) which can be found here: https://geometricbites.blogspot.com/2021/08/how-to-derive-tan38-sin38-and-cos38.html

The edge with length R√(2-√(2)) was actually derived in the
tan((3π)/8), sin((3π)/8) and cos((3π)/8) post, so doesn't need to be found again.

Part 1


 Part 2


 Part 3


 Part 4


Comments

Popular posts from this blog

Understanding Heuristics: A Practical Guide to Smarter Problem Solving

The Pythagram Defined

The Unicursal Pythagram